🎯 In this section you will learn

πŸ“Œ Even Functions

A function $f$ is even if $f(-x) = f(x)$ for all $x$ in its domain. The graph of an even function is symmetric about the y-axis.

$$ f(-x) = f(x) \quad \text{for all } x \text{ in the domain} $$
Function$f(-x)$Even?Graph Symmetry
$f(x) = x^2$$(-x)^2 = x^2$βœ“ Yesy-axis
$f(x) = \cos x$$\cos(-x) = \cos x$βœ“ Yesy-axis
$f(x) = |x|$$|-x| = |x|$βœ“ Yesy-axis
$f(x) = x^2 + 1$$(-x)^2 + 1 = x^2 + 1$βœ“ Yesy-axis
Example 1Testing for Even

Determine if $f(x) = 3x^4 - 2x^2 + 5$ is even.

β‘ 
Find $f(-x)$
$f(-x) = 3(-x)^4 - 2(-x)^2 + 5 = 3x^4 - 2x^2 + 5$
β‘‘
Compare with $f(x)$
$f(-x) = 3x^4 - 2x^2 + 5 = f(x)$
β‘’
Conclusion
$f(-x) = f(x)$, so $f$ is even.

πŸ“Œ Odd Functions

A function $f$ is odd if $f(-x) = -f(x)$ for all $x$ in its domain. The graph of an odd function is symmetric about the origin (rotational symmetry of $180^\circ$).

$$ f(-x) = -f(x) \quad \text{for all } x \text{ in the domain} $$
Function$f(-x)$$-f(x)$Odd?
$f(x) = x^3$$(-x)^3 = -x^3$$-x^3$βœ“ Yes
$f(x) = \sin x$$\sin(-x) = -\sin x$$-\sin x$βœ“ Yes
$f(x) = \frac{1}{x}$$\frac{1}{-x} = -\frac{1}{x}$$-\frac{1}{x}$βœ“ Yes
$f(x) = x^5 - x$$(-x)^5 - (-x) = -x^5 + x$$-(x^5 - x) = -x^5 + x$βœ“ Yes
Example 2Testing for Odd

Determine if $f(x) = 2x^3 - x$ is odd.

β‘ 
Find $f(-x)$
$f(-x) = 2(-x)^3 - (-x) = -2x^3 + x$
β‘‘
Find $-f(x)$
$-f(x) = -(2x^3 - x) = -2x^3 + x$
β‘’
Compare
$f(-x) = -2x^3 + x = -f(x)$
β‘£
Conclusion
$f(-x) = -f(x)$, so $f$ is odd.

πŸ“Œ Neither Even Nor Odd

Many functions are neither even nor odd. This happens when $f(-x) \neq f(x)$ and $f(-x) \neq -f(x)$.

Function$f(-x)$Even?Odd?
$f(x) = x^2 + x$$x^2 - x$No (β‰  $x^2 + x$)No (β‰  $-x^2 - x$)
$f(x) = e^x$$e^{-x}$NoNo
$f(x) = \ln x$$\ln(-x)$ undefinedNoNo
$f(x) = \sqrt{x}$$\sqrt{-x}$ undefinedNoNo
Example 3Neither Even Nor Odd

Determine if $f(x) = x^2 + 2x$ is even, odd, or neither.

β‘ 
Find $f(-x)$
$f(-x) = (-x)^2 + 2(-x) = x^2 - 2x$
β‘‘
Compare with $f(x)$
$f(-x) = x^2 - 2x \neq x^2 + 2x = f(x)$ β†’ not even
β‘’
Compare with $-f(x)$
$-f(x) = -x^2 - 2x \neq x^2 - 2x = f(-x)$ β†’ not odd
β‘£
Conclusion
$f$ is neither even nor odd.

πŸ–ΌοΈ Visual Demonstration

Interactive graph below. Click buttons to see even functions (y-axis symmetry) and odd functions (origin symmetry):

πŸ’‘ Algebraic Rules for Even and Odd

🎯 Why Does This Matter in Calculus?

PropertyEven FunctionsOdd Functions
Integral over symmetric interval $[-a, a]$ $\displaystyle \int_{-a}^{a} f(x) \, dx = 2\int_{0}^{a} f(x) \, dx$ $\displaystyle \int_{-a}^{a} f(x) \, dx = 0$
Derivative Derivative of an even function is odd Derivative of an odd function is even
Fourier Series Only cosine terms Only sine terms
Example 4Integral of an Odd Function

Evaluate $\int_{-2}^{2} x^3 \, dx$ using symmetry.

β‘ 
Identify symmetry
$f(x) = x^3$ is odd because $f(-x) = -x^3 = -f(x)$
β‘‘
Apply odd function rule
For odd functions, $\int_{-a}^{a} f(x) \, dx = 0$
β‘’
Result
$\int_{-2}^{2} x^3 \, dx = 0$
Example 5Integral of an Even Function

Evaluate $\int_{-2}^{2} x^2 \, dx$ using symmetry.

β‘ 
Identify symmetry
$f(x) = x^2$ is even because $f(-x) = x^2 = f(x)$
β‘‘
Apply even function rule
$\int_{-2}^{2} x^2 \, dx = 2\int_{0}^{2} x^2 \, dx = 2\left[\frac{x^3}{3}\right]_{0}^{2} = 2 \cdot \frac{8}{3} = \frac{16}{3}$
πŸ” Key Takeaway
Even functions are symmetric about the y-axis ($f(-x)=f(x)$). Odd functions are symmetric about the origin ($f(-x)=-f(x)$). Recognizing symmetry simplifies integrals significantly β€” odd functions integrate to zero over symmetric intervals.

πŸ“ Practice Problems

Problem 1Test for Even

Determine if $f(x) = x^6 - 4x^2$ is even, odd, or neither.

Show solution

$f(-x) = (-x)^6 - 4(-x)^2 = x^6 - 4x^2 = f(x)$. So $f$ is even.

Problem 2Test for Odd

Determine if $f(x) = x^5 + x^3$ is even, odd, or neither.

Show solution

$f(-x) = (-x)^5 + (-x)^3 = -x^5 - x^3 = -(x^5 + x^3) = -f(x)$. So $f$ is odd.

Problem 3Neither

Determine if $f(x) = x^3 + 1$ is even, odd, or neither.

Show solution

$f(-x) = -x^3 + 1$. This is not equal to $f(x) = x^3 + 1$ (not even), and not equal to $-f(x) = -x^3 - 1$ (not odd). So $f$ is neither.

Problem 4Integral Using Symmetry

Evaluate $\int_{-3}^{3} \sin x \, dx$ using symmetry.

Show solution

$\sin x$ is odd. For odd functions, $\int_{-a}^{a} f(x) \, dx = 0$. So $\int_{-3}^{3} \sin x \, dx = 0$.

Problem 5Integral Using Symmetry

Evaluate $\int_{-2}^{2} (x^4 + 1) \, dx$ using symmetry.

Show solution

$f(x) = x^4 + 1$ is even. $\int_{-2}^{2} (x^4 + 1) dx = 2\int_{0}^{2} (x^4 + 1) dx = 2\left[\frac{x^5}{5} + x\right]_{0}^{2} = 2\left(\frac{32}{5} + 2\right) = 2\left(\frac{32}{5} + \frac{10}{5}\right) = 2 \cdot \frac{42}{5} = \frac{84}{5}$.

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