Below are 20 practice problems covering all topics from Module 00: Functions & Graphs. Each problem includes a hidden solution β€” click the button to reveal the step-by-step answer.

Problem 01 Domain
Find the domain of \( f(x) = \frac{\sqrt{x-4}}{x} \).
Solution:
β€’ Square root condition: \( x - 4 \ge 0 \) β†’ \( x \ge 4 \)
β€’ Denominator condition: \( x \neq 0 \)
β€’ Intersection: \( x \ge 4 \) (automatically satisfies \( x \neq 0 \))
Domain: \( [4, \infty) \)
Problem 02 Domain
Find the domain of \( f(x) = \sqrt{x+2} \).
Solution:
β€’ Square root condition: \( x + 2 \ge 0 \) β†’ \( x \ge -2 \)
Domain: \( [-2, \infty) \)
Problem 03 Range
Find the range of \( f(x) = x^2 + 3 \).
Solution:
β€’ \( x^2 \ge 0 \) for all real \( x \)
β€’ \( x^2 + 3 \ge 3 \)
Range: \( [3, \infty) \)
Problem 04 Linear Function
Find the slope and y-intercept of \( f(x) = -4x + 7 \).
Solution:
β€’ Slope \( m = -4 \)
β€’ y-intercept \( b = 7 \)
Problem 05 Quadratic Function
Find the vertex of \( f(x) = x^2 + 4x - 5 \).
Solution:
β€’ Complete the square: \( x^2 + 4x - 5 = (x+2)^2 - 9 \)
β€’ Vertex: \( (-2, -9) \)
Problem 06 Rational Function
Find the domain of \( f(x) = \frac{3x}{x^2 - 9} \).
Solution:
β€’ Denominator: \( x^2 - 9 = (x-3)(x+3) = 0 \) β†’ \( x = 3 \) or \( x = -3 \)
Domain: \( (-\infty, -3) \cup (-3, 3) \cup (3, \infty) \)
Problem 07 Exponential Function
Evaluate \( f(3) \) if \( f(x) = 2 \cdot (1.5)^x \).
Solution:
β€’ \( f(3) = 2 \cdot (1.5)^3 = 2 \cdot 3.375 = 6.75 \)
Problem 08 Logarithmic Function
Find the domain of \( f(x) = \ln(x-1) \).
Solution:
β€’ Argument must be positive: \( x - 1 > 0 \) β†’ \( x > 1 \)
Domain: \( (1, \infty) \)
Problem 09 Trigonometric Function
Find \( \sin\left(\frac{5\pi}{6}\right) \).
Solution:
β€’ \( \frac{5\pi}{6} \) is in Quadrant II
β€’ Reference angle: \( \frac{\pi}{6} \)
β€’ Sine is positive in Quadrant II
β€’ \( \sin\left(\frac{5\pi}{6}\right) = \frac{1}{2} \)
Problem 10 Inverse Function
Find the inverse of \( f(x) = 3x - 5 \).
Solution:
β€’ Let \( y = 3x - 5 \)
β€’ Swap \( x \) and \( y \): \( x = 3y - 5 \)
β€’ Solve for \( y \): \( 3y = x + 5 \) β†’ \( y = \frac{x+5}{3} \)
β€’ \( f^{-1}(x) = \frac{x+5}{3} \)
Problem 11 Piecewise Function
Given \( f(x) = \begin{cases} x^2, & x < 0 \\ 2x+1, & x \ge 0 \end{cases} \), find \( f(-2) \) and \( f(3) \).
Solution:
β€’ \( f(-2) = (-2)^2 = 4 \)
β€’ \( f(3) = 2(3) + 1 = 7 \)
Problem 12 Transformations
Describe the transformation from \( f(x) = x^2 \) to \( g(x) = (x-3)^2 + 2 \).
Solution:
β€’ Inside \( (x-3) \) β†’ shift right 3 units
β€’ Outside \( +2 \) β†’ shift up 2 units
Problem 13 Composition
If \( f(x) = x^2 \) and \( g(x) = 2x - 1 \), find \( (f \circ g)(x) \) and \( (g \circ f)(x) \).
Solution:
β€’ \( (f \circ g)(x) = f(2x-1) = (2x-1)^2 = 4x^2 - 4x + 1 \)
β€’ \( (g \circ f)(x) = g(x^2) = 2x^2 - 1 \)
Problem 14 Even Function
Determine if \( f(x) = x^4 - 2x^2 \) is even, odd, or neither.
Solution:
β€’ \( f(-x) = (-x)^4 - 2(-x)^2 = x^4 - 2x^2 = f(x) \)
β€’ Therefore, \( f \) is even
Problem 15 Odd Function
Determine if \( f(x) = x^5 - x \) is even, odd, or neither.
Solution:
β€’ \( f(-x) = (-x)^5 - (-x) = -x^5 + x = -(x^5 - x) = -f(x) \)
β€’ Therefore, \( f \) is odd
Problem 16 Neither Even nor Odd
Determine if \( f(x) = x^2 + x \) is even, odd, or neither.
Solution:
β€’ \( f(-x) = x^2 - x \)
β€’ Not equal to \( f(x) \) β†’ not even
β€’ Not equal to \( -f(x) = -x^2 - x \) β†’ not odd
β€’ Therefore, \( f \) is neither even nor odd
Problem 17 Trigonometric Identity
Simplify \( \sin^2 x + \cos^2 x \).
Solution:
β€’ By the Pythagorean identity: \( \sin^2 x + \cos^2 x = 1 \)
Problem 18 Trigonometric Transformations
Find the amplitude and period of \( y = 3\sin(2x) \).
Solution:
β€’ Amplitude = \( |3| = 3 \)
β€’ Period = \( \frac{2\pi}{|2|} = \pi \)
Problem 19 Absolute Value
Rewrite \( |x - 2| \) as a piecewise function.
Solution:
β€’ \( |x - 2| = \begin{cases} x-2, & x \ge 2 \\ -(x-2), & x < 2 \end{cases} = \begin{cases} x-2, & x \ge 2 \\ -x+2, & x < 2 \end{cases} \)
Problem 20 Inverse Relationship
Simplify \( 10^{\log_{10} 5} \).
Solution:
β€’ Since exponentials and logarithms are inverses: \( 10^{\log_{10} 5} = 5 \)
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