What is Calculus I

a Critical Point?

A point where the derivative is zero or undefined — the candidates for maxima, minima, and saddle points of a function.

A critical point of a function \(f\) is any value \(x = c\) in its domain where either \(f'(c) = 0\) or \(f'(c)\) does not exist. These are the only places where a local maximum or minimum can occur — so finding critical points is the first step in every optimisation problem.

Think of it this way: at a peak or a valley, the tangent line is perfectly horizontal — slope zero. At a sharp corner (like the tip of \(|x|\)), the derivative doesn't exist. Both are critical points. Neither one is guaranteed to be a max or min — that requires further testing.

⛰️
Local Maximum
Function is higher here than at all nearby points. Derivative goes + → 0 → −.
🏔️
Local Minimum
Function is lower here than at all nearby points. Derivative goes − → 0 → +.
〰️
Saddle Point
Derivative is zero but it's neither a max nor a min. Sign of f' doesn't change.
🏔️
Standing at the top of a hill

At the peak of a hill, the ground is momentarily flat — zero slope in every direction. That's a critical point. Walking down the other side, the slope is negative. So the derivative went from positive (climbing) to zero (peak) to negative (descending). The sign change confirms it's a maximum.

⚠️
Critical ≠ extreme

Not every critical point is a max or min. Consider \(f(x) = x^3\) at \(x = 0\): \(f'(0) = 0\), so it's a critical point — but the function keeps increasing through zero. It's a saddle point (also called an inflection point with zero slope). Always test after finding critical points.

Green = local max · Red = local min · Gold = saddle point · Tangent lines shown at each critical point
1
Find \(f'(x)\)
Differentiate the function using whatever rules apply — power rule, chain rule, product rule, etc.
2
Set \(f'(x) = 0\) and solve
These give the "stationary points" — where the tangent line is horizontal.
3
Find where \(f'(x)\) is undefined
Check for division by zero, square roots of negatives, or other domain issues in \(f'\). These are also critical points if \(x\) is in the domain of \(f\).
4
Classify using first or second derivative test
Determine whether each critical point is a local max, local min, or saddle point.
First Derivative Test
Check the sign of f' around c
+ → −: local maximum
− → +: local minimum
no sign change: saddle point

Works even when the second derivative doesn't exist.
Second Derivative Test
Evaluate f″(c)
f″(c) < 0: local maximum (concave down)
f″(c) > 0: local minimum (concave up)
f″(c) = 0: inconclusive — use first derivative test

Faster when f″ is easy to compute.
Example 1
\(f(x) = x^3 - 3x\)
\(f'(x) = 3x^2 - 3 = 0\)
\(x = \pm 1\)
\(f''(1) = 6 > 0\) → min at \(x=1\)
\(f''(-1) = -6 < 0\) → max at \(x=-1\)
Example 2 — Saddle
\(f(x) = x^3\)
\(f'(0) = 0\) → critical point
\(f''(0) = 0\) → inconclusive
First deriv test: + → + (no change)
→ saddle point at \(x = 0\)
Example 3 — Undefined f'
\(f(x) = |x|\)
\(f'(0)\) does not exist (sharp corner)
→ critical point at \(x = 0\)
First deriv: − → + → local min
Example 4 — Full process
\(f(x) = x^4 - 4x^2\)
\(f'= 4x^3 - 8x = 4x(x^2-2) = 0\)
\(x = 0, \pm\sqrt{2}\)
Test each: max at 0, minima at \(\pm\sqrt{2}\)
✗ Assuming every critical point is a max or min
Critical points are only candidates. A saddle point satisfies \(f'(c) = 0\) but is neither a max nor a min. Always classify after finding the critical points — never assume.
✗ Forgetting critical points where f' is undefined
Setting \(f'(x) = 0\) finds stationary points, but there may also be critical points where \(f'\) doesn't exist. Check the denominator of \(f'\), any roots, and other potential undefined spots.
✗ Confusing local and global extrema
A local max is just the highest point in a neighbourhood — not necessarily the highest point overall. To find the global max on \([a,b]\), compare all local maxima and also evaluate \(f\) at the endpoints \(a\) and \(b\).

Ready to test your knowledge?

Critical points and optimisation are core topics in every Calculus I quiz.

Go to Calculus I Quizzes →